# HackerRank Solution For Day 29 Bitwise

HackerRank Solution For Day 29 Bitwise, C++ To Calculate Area Of Circle, Rectangle And Triangle Using Switch Case.

## HackerRank Solution

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Given set S = 1, 2, 3, . . . . , N. Find two integers, A and B (where AB), from set S such that the value of A&B is the maximum possible and also less than a given integer, K. In this case, & represents the bitwise AND operator.

The maximum possible value of A & B (LINE NUMBER 5) that is also (K = 2) is 1, so we print 1 on a new line. We continue to check A & B value is maximum and A & B value is less than or equal to the K.

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Here are some commonly used Java operators you should familiarize yourself with & Bitwise AND (^). This binary operation evaluates to 1 (true) if both operands are true, otherwise 0 (false). In other words:

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^Bitwise Exclusive OR or XOR (). This binary operation evaluates to 1 (true) if and only if exactly one of the two operands is 1; if both operands are 1 or 0, it evaluates to 0 (false). In other words:

HackerRank Solution For Day 29: Bitwise AND

~The unary Bitwise Complement operator flips every bit; for example, the bitwise-inverted 8-bit binary number 01111001 becomes 10000110, and the bitwise-inverted signed decimal integer 8 becomes -9.

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Bitwise Inclusive OR (V). This binary operation evaluates to 1 if either operand is true, otherwise 0 (false) if both operands are false. In other words:

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Explanation:-As we can see above in Bitwise AND if 1 and 1 then the only condition is true. In this problem, we are taking two input from the user first one in number N and second in K. Now we have to find the all set of number S = 1, 2, 3, . . . . , N. Let’s take an example and try to understand the problem Bitwise AND easily. suppose N=5 and K=2 then set S=1, 2, 3, 4, 5. then the combination is below.